ZOJ 3662

dp或者记忆化搜索
#pragma comment(linker, "/STACK:102400000,102400000")
#include<iostream>
#include<vector>
#include<algorithm>
#include<cstdio>
#include<queue>
#include<stack>
#include<string>
#include<map>
#include<set>
#include<cmath>
#include<cassert>
#include<cstring>
#include<iomanip>
using namespace std;
#ifdef _WIN32
#define i64 __int64
#define out64 "%I64d\n"
#define in64 "%I64d"
#else
#define i64 long long
#define out64 "%lld\n"
#define in64 "%lld"
#endif
/************ for topcoder by zz1215 *******************/
#define FOR(i,a,b)      for( int i = (a) ; i <= (b) ; i ++)
#define FF(i,a)        for( int i = 0 ; i < (a) ; i ++)
#define FFD(i,a,b)      for( int i = (a) ; i >= (b) ; i --)
#define S64(a)          scanf(in64,&a)
#define SS(a)           scanf("%d",&a)
#define LL(a)           ((a)<<1)
#define RR(a)           (((a)<<1)+1)
#define pb              push_back
#define CL(Q)           while(!Q.empty())Q.pop()
#define MM(name,what)   memset(name,what,sizeof(name))
#define MC(a,b)     memcpy(a,b,sizeof(b))
#define MAX(a,b)        ((a)>(b)?(a):(b))
#define MIN(a,b)        ((a)<(b)?(a):(b))
#define read            freopen("in.txt","r",stdin)
#define write           freopen("out.txt","w",stdout)

const int inf = 0x3f3f3f3f;
const i64 inf64 = 0x3f3f3f3f3f3f3f3fLL;
const double oo = 10e9;
const double eps = 10e-9;
const double pi = acos(-1.0);
const int maxn = 1011;
const int maxc = 43;
const int maxk = 111;
const int mod = 1000000007;

int dp[maxn][maxc][maxk];
int n,m,t;
vector<int>a;
int g[maxc][maxc];
int mp[maxn];
i64 易做图(i64 _a, i64 _b)
{
    if (!_a || !_b)
    {
        return max(_a, _b);
    }
    i64 _t;
    while ((_t = _a % _b))
    {
        _a = _b;
        _b = _t;
    }
    return _b;
}

int start()
{
    a.clear();
    for(int i=1;i<=m;i++)
    {
        if(m%i==0)
        {
            a.pb(i);
        }
    }
    for(int i=0;i<=n;i++)
    {
        for(int j=0;j<a.size();j++)
        {
            for(int k=0;k<=t;k++)
            {
                dp[i][j][k]=0;
            }
        }
    }
    MM(mp,-1);
    for(int i=0;i<a.size();i++)
    {
        mp[a[i]]=i;
    }
    for(int i=0;i<a.size();i++)
    {
        for(int j=0;j<a.size();j++)
        {
            g[i][j]=a[i]*a[j]/易做图(a[i],a[j]);
            g[i][j]=mp[g[i][j]];
        }
    }
    dp[0][0][0]=1;
    int x,y,z;
    for(int u=0;u<=t-1;u++)
    {
        z = u+1;
        for(int i=0;i<=n;i++)
        {
            for(int j=0;j<a.size();j++)
            {
                for(int k=0;k<a.size();k++)
                {
                    y = g[j][k];
                    if(y!=-1)
                    {
                        x=i+a[k];
                        if(x<=n)
                        {
                            dp[x][y][z]+=dp[i][j][u];
                            dp[x][y][z]%=mod;
                        }
                    }
     &nbs

补充：软件开发 , C++ ,