UVA 12554 (13.11.02)

Problem A

A Special "[H]appy Birthday" Song!!!

There are n people (excluding myself) in my 30th birthday party. They sing the traditional "happy birthday" song:

Happy birthday to you! Happy birthday to you! Happy birthday to Rujia! Happy birthday to you!!!

Since I love music, I want to hear something more interesting, not that everyone sings together. Ah yes, I want one person to sing one word!

For example, there are three people: Mom, Dad, Girlfriend, I'd like them to sing like this:

Mom: Happy

Dad: birthday

Girlfriend: to

Mom: you

Dad: Happy

Girlfriend: birthday

Mom: to

Dad: you

Girlfriend: Happy

Mom: birthday

Dad: to

Girlfriend: Rujia

Mom: Happy

Dad: birthday

Girlfriend: to

Mom: you

Very nice, right? What if there are more than 16 people? That's easy: repeat the song until everyone has sung at least once :)

Please, don't stop in the middle of the song.

Input

There is only one test case. The first line contains a single integer n (1<=n<=100). Then each of the next n lines contains a capitalized name (i.e. one upper-case letter followed by zero or more lower-case letters). Each name contains at most 100 characters and do not have whitespace characters inside.

Output

Output the song, formatted as above.

Sample Input

Mom

Dad

Girlfriend

Output for the Sample Input

Mom: Happy

Dad: birthday

Girlfriend: to

Mom: you

Dad: Happy

Girlfriend: birthday

Mom: to

Dad: you

Girlfriend: Happy

Mom: birthday

Dad: to

Girlfriend: Rujia

Mom: Happy

Dad: birthday

Girlfriend: to

Mom: you

水题不想解释题意了

但是注意一下坑点：注意人数大于16人的情况～

AC代码：

#include<stdio.h>  
  
char name[250][250];  
int n;  
  
int main() {  
    scanf("%d", &n);  
    getchar();  
    for(int i = 0; i < n; i++)  
        gets(name[i]);  
    int k;  
    if(n <= 16)  
        k = 16;  
    else {  
        k = 16 * (n / 16);  
        if(n % 16 > 0)  
            k += 16;  
    }  
    for(int i = 0; i < k; i++) {  
        printf("%s: ", name[i%n]);  
        if(i % 16 == 11) {  
            puts("Rujia");  
            continue;  
        }  
        if(i % 4 == 0)  
            puts("Happy");  
        else if(i % 4 == 1)  
            puts("birthday");  
        else if(i % 4 == 2)  
            puts("to");  
        else  
            puts("you");  
    }  
    return 0;  
}

补充：软件开发 , C++ ,