实现对16位数的反转(倒序变换)

一个算法
unsigned short SwapBit16(unsigned short Data)
{
    int i;
    unsigned short Dest;

    Dest = 0;
    for(i=0;i<8;i++)
        Dest |= ((((Data&(1<<i))?1:0)<<(15-i)) + (((Data&(1<<(15-i)))?1:0)<<i));

    return Dest;

}

上面这个函数实现对16位数的反转（倒序变换）。
实现的思路，可以使用如下方法来测试一下。

这个是一个测试函数
#include <stdio.h>
int main(void )
{
    int i;
    unsigned short Data=45918;

    int Dest = 0;
    for(i=0;i<8;i++){
         printf("Date1 is 0x%x \n",(((Data&(1<<i))?1:0)<<(15-i)));
         printf("Date2 is 0x%x \n",(((Data&(1<<(15-i)))?1:0)<<i));
         printf("Date2 and Date1 is 0x%x \n",((((Data&(1<<i))?1:0)<<(15-i)))+(((Data&(1<<(15-i)))?1:0)<<i));
        Dest |= ((((Data&(1<<i))?1:0)<<(15-i)) + (((Data&(1<<(15-i)))?1:0)<<i));
    }
        printf("the 0b1011001101011110 end the Date is 0x%x\n",Dest);
    return Dest;

}
下面是测试信息结果：
Date1 is 0x0
Date2 is 0x1
Date2 and Date1 is 0x1
Date1 is 0x4000
Date2 is 0x0
Date2 and Date1 is 0x4000
Date1 is 0x2000
Date2 is 0x4
Date2 and Date1 is 0x2004
Date1 is 0x1000
Date2 is 0x8
Date2 and Date1 is 0x1008
Date1 is 0x800
Date2 is 0x0
Date2 and Date1 is 0x800
Date1 is 0x0
Date2 is 0x0
Date2 and Date1 is 0x0
Date1 is 0x200
Date2 is 0x40
Date2 and Date1 is 0x240
Date1 is 0x0
Date2 is 0x80
Date2 and Date1 is 0x80
the 0b1011001101011110 end the Date is 0x7acd

从结果可看出，实现思想是15<-->0,14<-->1,13<-->2,......8<-->7相交换，具体怎么实现的，你自己可以深入分析一下。。

摘自：gududesiling的专栏

补充：软件开发 , C语言 ,