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求vb md5加解密

If password.Text = "haha" Then
Shell ("cmd.exe"), vbNormalFocus
Else

msgbox "密码不对!"

 

 

本来是想设置密码,不输密码就不能运行指定程序。但是这样太简单了,别人直接用记事本打开这个exe就可以看到密码了。所以希望大家帮我写个md5解密的过程,完善这个小程序。

 

假如 密码haha MD5加密后为 dadsasdads ,加密后的结果大家可以到 www.cmd5.com 查看

 

那么原程序就变为  dim  md5mima 

md5mima = md5("dadsasdads")  

If password.Text = md5mima Then 

 

只要源代码中不出现   haha  这个原密码就可以。

要写的就是 md5() 这个 function 过程  

就这样简单。。。   我不知道上面的语法有没有写对,不会vb,但我相信大家明白意思。会的帮我写个程序,不要编译好的exe  ,要全部的源代码 。

 

追问:不懂啊。。。。。。 类已经建好了  是改成这样么  :

 

Private Sub cmd_Click()
    Dim mymd5 As New ClsAPIMD5
    Dim md5str As String
    md5str = mymd5.HashString("2b6fe62a63afe561", md5)
    Set mymd5 = Nothing
If password.Text = md5str Then
Shell ("cmd.exe"), vbNormalFocus
Else
MsgBox "抱歉,非请莫入!"

End
End If
End Sub

 

 

2b6fe62a63afe561
 是 haha  md5加密后的 字符

答案:代码很多。仔细看

先建一个类Class Module 取名为ClsAPIMD5

复制下面的代码到类里:

'API 做的MD5类

Option Explicit


Private Declare Function CryptAcquireContext Lib "advapi32.dll" _
   Alias "CryptAcquireContextA" ( _
   ByRef phProv As Long, _
   ByVal pszContainer As String, _
   ByVal pszProvider As String, _
   ByVal dwProvType As Long, _
   ByVal dwFlags As Long) As Long

Private Declare Function CryptReleaseContext Lib "advapi32.dll" ( _
   ByVal hProv As Long, _
   ByVal dwFlags As Long) As Long

Private Declare Function CryptCreateHash Lib "advapi32.dll" ( _
   ByVal hProv As Long, _
   ByVal Algid As Long, _
   ByVal hKey As Long, _
   ByVal dwFlags As Long, _
   ByRef phHash As Long) As Long

Private Declare Function CryptDestroyHash Lib "advapi32.dll" ( _
   ByVal hHash As Long) As Long

Private Declare Function CryptHashData Lib "advapi32.dll" ( _
   ByVal hHash As Long, _
   pbData As Any, _
   ByVal dwDataLen As Long, _
   ByVal dwFlags As Long) As Long

Private Declare Function CryptGetHashParam Lib "advapi32.dll" ( _
   ByVal hHash As Long, _
   ByVal dwParam As Long, _
   pbData As Any, _
   pdwDataLen As Long, _
   ByVal dwFlags As Long) As Long

Private Const PROV_RSA_FULL = 1

Private Const ALG_CLASS_HASH = 32768

Private Const ALG_TYPE_ANY = 0

Private Const ALG_SID_MD2 = 1
Private Const ALG_SID_MD4 = 2
Private Const ALG_SID_MD5 = 3
Private Const ALG_SID_SHA1 = 4

Enum HashAlgorithm
   md2 = ALG_CLASS_HASH Or ALG_TYPE_ANY Or ALG_SID_MD2
   MD4 = ALG_CLASS_HASH Or ALG_TYPE_ANY Or ALG_SID_MD4
   md5 = ALG_CLASS_HASH Or ALG_TYPE_ANY Or ALG_SID_MD5
   SHA1 = ALG_CLASS_HASH Or ALG_TYPE_ANY Or ALG_SID_SHA1
End Enum

Private Const HP_HASHVAL = 2
Private Const HP_HASHSIZE = 4

Function HashString( _
   ByVal Str As String, _
   Optional ByVal Algorithm As HashAlgorithm = md5) As String
Dim hCtx As Long
Dim hHash As Long
Dim lRes As Long
Dim lLen As Long
Dim lIdx As Long
Dim abData() As Byte

   ' Get default provider context handle
   lRes = CryptAcquireContext(hCtx, vbNullString, _
           vbNullString, PROV_RSA_FULL, 0)

   If lRes <> 0 Then

      ' Create the hash
      lRes = CryptCreateHash(hCtx, Algorithm, 0, 0, hHash)

      If lRes <> 0 Then

         ' Hash the string
         lRes = CryptHashData(hHash, ByVal Str, Len(Str), 0)

         If lRes <> 0 Then
           
            ' Get the hash lenght
            lRes = CryptGetHashParam(hHash, HP_HASHSIZE, lLen, 4, 0)

            If lRes <> 0 Then

                ' Initialize the buffer
                ReDim abData(0 To lLen - 1)

                ' Get the hash value
                lRes = CryptGetHashParam(hHash, HP_HASHVAL, abData(0), lLen, 0)

                If lRes <> 0 Then

                    ' Convert value to hex string
                    For lIdx = 0 To UBound(abData)
                        HashString = HashString & _
                                     Right$("0" & Hex$(abData(lIdx)), 2)
                    Next

                End If

            End If

         End If

         ' Release the hash handle
         CryptDestroyHash hHash

      End If
     
   End If

   ' Release the provider context
   CryptReleaseContext hCtx, 0

   ' Raise an error if lRes = 0
   If lRes = 0 Then Err.Raise Err.LastDllError

End Function

Function HashFile( _
   ByVal Filename As String, _
   Optional ByVal Algorithm As HashAlgorithm = md5) As String
Dim hCtx As Long
Dim hHash As Long
Dim lFile As Long
Dim lRes As Long
Dim lLen As Long
Dim lIdx As Long
Dim abHash() As Byte

   ' Check if the file exists (not the best method BTW!)
   If Len(Dir$(Filename)) = 0 Then Err.Raise 53
  
   ' Get default provider context handle
   lRes = CryptAcquireContext(hCtx, vbNullString, _
           vbNullString, PROV_RSA_FULL, 0)

   If lRes = 0 And Err.LastDllError = &H80090016 Then
  
      ' There's no default keyset container!!!
      ' Get the provider context and create
      ' a default keyset container
      lRes = CryptAcquireContext(hCtx, vbNullString, _
               vbNullString, PROV_RSA_FULL, CRYPT_NEWKEYSET)
   End If
  
   If lRes <> 0 Then

      ' Create the hash
      lRes = CryptCreateHash(hCtx, Algorithm, 0, 0, hHash)

      If lRes <> 0 Then

         ' Get a file handle
         lFile = FreeFile
        
         ' Open the file
         Open Filename For Binary As lFile
        
         If Err.Number = 0 Then
        
            Const BLOCK_SIZE As Long = 32 * 1024& ' 32K
            ReDim abBlock(1 To BLOCK_SIZE) As Byte
  &nb

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