答案:1、纯粹的截取字符串
function cutstr(thestr1,strlen)
dim l,t,c
l=len(thestr1)
if l<1 then exit function
t=0
for dxy1=1 to l
c=Abs(asc(Mid(thestr1,dxy1,1)))
if c>255 then
t=t+2
else
t=t+1
end if
if t>=strlen then
thev=mid(thestr1,1,dxy1)
exit for
else
thev=thestr1
end if
next
cutstr=thev
end function
2、截取字符串,不足用空格补上
function cutstr(thestr,strlen)
dim l,t,c
l=len(thestr)
t=0
for dxy=1 to l
c=Abs(asc(Mid(thestr,dxy,1)))
if c>255 then
t=t+2
else
t=t+1
end if
if t>=strlen then
thev=left(thestr,dxy)
exit for
else
bu=strlen-t
for bui=1 to bu
strbu=" "
strbuall=strbuall&strbu
next
thev=thestr&strbuall
strbu=""
strbuall=""
end if
next
cutstr=thev
end function
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