C语言高手进！

定义一个结构体数组，存放 10个学生的学号，姓名，三门课的成绩，输出单门课成绩最高的学生的学号、姓名、以及该门课程的成绩，输出三门 课程的平均分数最高的学生的学号、姓名及其平均分，再将 10个学生按照平均分数从高到低进行排序，输出结果。

追问：问一下，又没调试过呢？

答案：如下，望采纳：
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <memory>
#include <cstring>
using namespace std;
typedef struct Student
{
    char num[20];
    char name[20];
    double score[3];
    double aver;
}STU;
STU s[10];
int i,j;
int main()
{
    double max1=0,max2=0,max3=0,max4=0;
    int pos1=0,pos2=0,pos3=0,pos4=0;
    printf("Input the data(Number,Name & 3 Scores) of 10 students:\n");
    for(i=0;i<10;i++)
    {
       scanf("%s %s %lf %lf %lf",s[i].num,s[i].name,&(s[i].score[0]),&(s[i].score[1]),&(s[i].score[2]));
       s[i].aver=(s[i].score[0]+s[i].score[1]+s[i].score[2])/3.0;
    }
    for(j=0;j<10;j++)
    {
       if(s[j].score[0]>max1)
       {
          max1=s[j].score[0];
          pos1=j;
       }
       if(s[j].score[1]>max2)
       {
          max2=s[j].score[1];
          pos2=j;
       }
       if(s[j].score[2]>max3)
       {
          max3=s[j].score[2];
          pos3=j;
       }
       if(s[j].aver>max4)
       {
          max4=s[j].aver;
          pos4=j;
       }
    }
    printf("The highest of score 1 is:\n");
    printf("%s %s %lf\n",s[pos1].num,s[pos1].name,s[pos1].score[0]);
    printf("The highest of score 2 is:\n");
    printf("%s %s %lf\n",s[pos2].num,s[pos2].name,s[pos2].score[1]);
    printf("The highest of score 3 is:\n");
    printf("%s %s %lf\n",s[pos3].num,s[pos3].name,s[pos3].score[2]);
    printf("The highest average is:\n");
    printf("%s %s %lf\n",s[pos4].num,s[pos4].name,s[pos4].aver);
    for(i=0;i<9;i++)
    {
       for(j=i+1;j<10;j++)
       {
          if(s[j].aver>s[i].aver)
             swap(s[j],s[i]);
       }
    }
    printf("The list is:\n");
    for(int j=0;j<10;j++)
       printf("%s %s %lf\n",s[j].num,s[j].name,s[j].aver);
    system("pause");
    return 0;
}

 
简单易懂，有问题在线修改！
==============================================
#include<stdio.h>
#define HUMMAX 10 //一个班级人数最大值
#define CLASSMAX 3  //课程数
 struct Student
 {
     char Num[10];  //学号
     char Name[10];  //姓名
     float Score[CLASSMAX];  //三门成细
 }s[HUMMAX];
 
 void Input_StudentInfo();  //输入学生信息
 void Output_ClassGood();  //单门课成绩最高信息
 void Output_AvgGood();  //平均成绩最高信息
 void Output_AvgOrder();  //平均分排序信息
 void main()
 {
     Input_StudentInfo();
     Output_ClassGood();
     Output_AvgGood();
     Output_AvgOrder();
 }
 void Input_StudentInfo()
 {
    int i=0,j=0;
 printf("Input Student Info:\n");
    for (i=0; i<HUMMAX; i++)
    {
       printf("NO.%d\n",i);
       printf("Num:"); scanf("%s",s[i].Num);
       printf("Name:"); scanf("%s",s[i].Name);
       for (j=0; j<CLASSMAX; j++)
       {
   printf("Score%d:",j);
   scanf("%f",&s[i].Score[j]);
       }
    }
 }
 void Output_ClassGood()
 {
    float MaxScore=0;
    int i=0,j=0,k=0;
    for (i=0; i<HUMMAX; i++)
       for (j=0; j<CLASSMAX; j++)
          if (s[i].Score[j]>MaxScore)
          {
              MaxScore=s[i].Score[j];
              k=i;
          }
     printf("\n\nA Class Score Good:\n");
     printf("Num:%s\nName:%s\n",s[k].Num,s[k].Name);
     printf("Score1~3：%f %f %f\n",s[k].Score[0],s[k].Score[1],s[k].Score[2]);
 }
 void Output_AvgGood()
 {
    float Avg=0,Sum=0;
    int i=0,j=0,k=0;
    for (i=0; i<HUMMAX; i++)
    {
       for (j=0; j<HUMMAX; j++)
          Sum+=s[i].Score[j];
       if (Sum>Avg)
       {
          Avg=Sum;
          k=i;
       }
    }
     printf("\n\nAvg Class Score Good:\n");
     printf("Num:%s\nName:%s\n",s[k].Num,s[k].Name);
     printf("Score1~3：%f %f %f\n",s[k].Score[0],s[k].Score[1],s[k].Score[2]);
  printf("Average Score:",s[k].Score[0]+s[k].Score[1]+s[k].Score[2]);
 }
 void Output_AvgOrder()
 {
     float Avg,TAvg;
     Student ts;
     int i=0,j=0,k=0;
     for (i=0; i<HUMMAX-1; i++)
     {  
        Avg=0;
        for (k=0; k<CLASSMAX; k++)
           Avg+=s[i].Score[k];
        for (j=i+1; j<HUMMAX; j++)
        {
           TAvg=0;
           for (k=0; k<CLASSMAX; k++)
              TAvg+=s[j].Score[k];
           if (TAvg>Avg)
   &nb

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