在C#中实现矩阵运算

环境：

主机:XP

开发环境:VS2008

功能:

在C#中实现矩阵运算

源代码：

[csharp]
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

//矩阵数据结构
//二维矩阵
class _Matrix
{
    public int m;
    public int n;
    public float[] arr;

    //初始化
    public _Matrix()
    {
        m = 0;
        n = 0;
    }

    public _Matrix(int mm,int nn)
    {
        m = mm;
        n = nn;
    }

    //设置m
    public void set_mn(int mm,int nn)
    {
        m = mm;
        n = nn;
    }

    //设置m
    public void set_m(int mm)
    {
        m = mm;
    }

    //设置n
    public void set_n(int nn)
    {
        n = nn;
    }

    //初始化
    public void init_matrix()
    {
        arr = new float[m * n];
    }

    //释放
    public void free_matrix()
    {
        //delete [] arr;
    }

    //读取i,j坐标的数据
    //失败返回-31415,成功返回值
    public float read(int i,int j)
    {
        if (i >= m || j >= n)
        {
            return -31415;
        }

        //return *(arr + i * n + j);
        return arr[i * n + j];
    }

    //写入i,j坐标的数据
    //失败返回-1,成功返回1
    public int write(int i,int j,float val)
    {
        if (i >= m || j >= n)
        {
            return -1;
        }

        arr[i * n + j] = val;
        return 1;
    }
};

//二维运算类
class _Matrix_Calc
{
    //初始化
    public _Matrix_Calc()
    {

    }

    //C = A + B
    //成功返回1,失败返回-1
    public int add(ref _Matrix A,ref _Matrix B,ref _Matrix C)
    {
        int i = 0;
        int j = 0;

        //判断是否可以运算
        if (A.m != B.m || A.n != B.n ||
            A.m != C.m || A.n != C.n)
        {
            return -1;
        }
        //运算
        for (i = 0;i < C.m;i++)
        {
            for (j = 0;j < C.n;j++)
            {
                C.write(i,j,A.read(i,j) + B.read(i,j));
            }
        }

        return 1;
    }

    //C = A - B
    //成功返回1,失败返回-1
    public int subtract(ref _Matrix A,ref _Matrix B, ref _Matrix C)
    {
        int i = 0;
        int j = 0;

        //判断是否可以运算
        if (A.m != B.m || A.n != B.n ||
            A.m != C.m || A.n != C.n)
        {
            return -1;
        }
        //运算
        for (i = 0;i < C.m;i++)
        {

补充：软件开发 , C# ,