asp下用datediff实现计算两个时间差的函数

答案：计算两个时间差的函数 
'****************************** 
'||Function TimeDiff(sBegin, sEnd) 
'||本函数计算两个时间的差，可以不用更改直接使用 
'||作者：machinecat 2001/10/26 
'****************************** 
'****************************** 
'注：首先需要判断用户输入的sBegin与sEnd之间的大小 
'可以通过DataDiff函数获得两者之间的时间差，不需要进行复杂的时间换算 
'****************************** 
Function TimeDiff(sBegin, sEnd) 
Dim iHourB, iMinuteB, iSecondB, iMiniSecondB 
Dim iHourE, iMinuteE, iSecondE, iMiniSecondE 
Dim dTimeB, dTimeE, dTimeDiff 
Dim iHour, iMinute, iSecond, iMiniSecond 
iHourB = clng(Left(sBegin, 2)) 
iMinuteB = clng(Mid(sBegin, 4, 2)) 
iSecondB = clng(Mid(sBegin, 7, 2)) 
iMiniSecondB = clng(Mid(sBegin, 10, 4)) 
iHourE = clng(Left(sEnd, 2)) 
iMinuteE = clng(Mid(sEnd, 4, 2)) 
iSecondE = clng(Mid(sEnd, 7, 2)) 
iMiniSecondE = clng(Mid(sEnd, 10, 4)) 
dTimeB = iHourB * 3600 + iMinuteB * 60 + iSecondB + iMiniSecondB / 1000 
dTimeE = iHourE * 3600 + iMinuteE * 60 + iSecondE + iMiniSecondE / 1000 
dTimeDiff = dTimeE - dTimeB 
iHour = Int(dTimeDiff / 3600) 
dTimeDiff = dTimeDiff - iHour * 3600 
iMinute = Int(dTimeDiff / 60) 
dTimeDiff = dTimeDiff - iMinute * 60 
iSecond = Int(dTimeDiff) 
dTimeDiff = dTimeDiff - Int(dTimeDiff) 
iMiniSecond = dTimeDiff 
TimeDiff = iHour & "小时" & iMinute & "分钟" & iSecond & FormatNumber(iMiniSecond, 3) & "秒" 
End Function  

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