hdu2516 取石子游戏-----找规律

取石子游戏
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1394 Accepted Submission(s): 780

Problem Description
1堆石子有n个,两人轮流取.先取者第1次可以取任意多个，但不能全部取完.以后每次取的石子数不能超过上次取子数的2倍。取完者胜.先取者负输出"Second win".先取者胜输出"First win".

Input
输入有多组.每组第1行是2<=n<2^31. n=0退出.

Output
先取者负输出"Second win". 先取者胜输出"First win".
参看Sample Output.

Sample Input
2
13
10000
0

Sample Output
Second win
Second win
First win

Source
ECJTU 2008 Autumn Contest

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必败点是斐波那契数列
[cpp]
#include<iostream>
#include<cstdlib>
#include<stdio.h>
using namespace std;
#define ll __int64
ll f[45];
int main()
{
    f[0]=2;f[1]=3;
    for(int i=2;i<=44;i++)
    f[i]=f[i-1]+f[i-2];
    ll n;
    while(scanf("%I64d",&n)&&n)
    {
        int i;
        for(i=0;i<=44;i++)
        {
            if(f[i]==n)
            break;
        }
        if(i<44) puts("Second win");
        else puts("First win");

    }
}
/*
Sample Input
2
13
10000
0

Sample Output
Second win
Second win
First win
*/

补充：软件开发 , C++ ,