Reverse Integer @LeetCode

package Level2;  
  
/** 
 *  
 * Reverse Integer  
 *  
 * Reverse digits of an integer. 
 
Example1: x = 123, return 321 
Example2: x = -123, return -321 
 
click to show spoilers. 
 
Have you thought about this? 
Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! 
 
If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100. 
 
Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases? 
 
Throw an exception? Good, but what if throwing an exception is not an option? You would then have to re-design the function (ie, add an extra parameter). 
 *  
 */  
public class S7 {  
  
    public static void main(String[] args) {  
        System.out.println(reverse(1234));  
        System.out.println(reverse(100));  
    }  
  
    public static int reverse(int x) {  
        int res = 0;  
        // 123 -> 3  
        //  12 -> 30 + 2  
        //    1 -> 320 + 1  
        while(x != 0){  
            // 每一次都在原来结果的基础上变大10倍，再加上余数  
            res = res*10 + x%10;  
            x /= 10;  
        }  
        return res;  
    }  
}

补充：软件开发 , Java ,