HDU3346：Lucky Number

Problem Description
To Chinese people, 8 is a lucky number. Now your task is to judge if a number is lucky.
We say a number is lucky if it’s a multiple of 8, or the sum of digits that make up the number is a multiple of 8, or the sum of every digit’s square is a multiple of 8.

Input
The first line contains an integer stands for the number of test cases.
Each test case contains an integer n (n >= 0).

Output
For each case, output “Lucky number!” if the number is lucky, otherwise output “What a pity!”.

Sample Input
2
0
8

Sample Output
Lucky number!
Lucky number!

一开始没有注意到每个数字的平方数的和

[cpp]
#include <stdio.h>

int main()
{
    int t;
    scanf("%d",&t);
    while(t--)
    {
        int a,flag = 0,sum1 = 0,sum2 = 0;
        scanf("%d",&a);
        if(a%8 == 0)
            flag = 1;
        else
        {
            while(a)
            {
                sum1+=a%10;
                sum2+=(a%10)*(a%10);
                a/=10;
            }
            if(sum1%8 == 0)
                flag = 1;
            else if(sum2%8 == 0)
                flag = 1;
        }
        if(flag)
            printf("Lucky number!\n");
        else
            printf("What a pity!\n");
    }

    return 0;
}

#include <stdio.h>

int main()
{
    int t;
    scanf("%d",&t);
    while(t--)
    {
        int a,flag = 0,sum1 = 0,sum2 = 0;
        scanf("%d",&a);
        if(a%8 == 0)
            flag = 1;
        else
        {
            while(a)
            {
                sum1+=a%10;
                sum2+=(a%10)*(a%10);
                a/=10;
            }
            if(sum1%8 == 0)
                flag = 1;
            else if(sum2%8 == 0)
                flag = 1;
        }
        if(flag)
            printf("Lucky number!\n");
        else
            printf("What a pity!\n");
    }

return 0;
}

补充：软件开发 , C++ ,