答案:#includeint t, max;//t存放a与b的较大值,max存放最大值
using namespace std;
int min(int a2, int b2, int c2)
{
return (a2b1 ? ((a1 > c1) ? a1:c1) : ((b1 > c1) ? b1:c1));
}
void main()
{
int a, b, c;
int n, m;
cin>>a>>b>>c;
n = max(a, b, c);
cout<<"max="<<n<<endl;
m = min(a, b, c);
cout<<"min="<<m<<endl;
}
t=a>b?a:b;
max=t>c?t:c;#include <iostream>
using namespace std;
int main()
{
int a,b,c;
cin>>a>>b>>c;
int max = a>b?(a>c?a:c):(b>c?b:c);
int min = a<b?(a<c?a:c):(b<c?b:c);
cout<<"max:"<<max<<endl<<"min:"<<min<<endl;
return 0;
}