hdu 2440 Watch out the Animal(凸包+费马点)
读懂了题的话就不难发现是要求费马点,不过输入点的顺序是不一定的,而且求的是凸包的费马点,不是所有点的费马点。。。#include<algorithm> #include<iostream> #include<cstring> #include<cstdlib> #include<fstream> #include<sstream> #include<bitset> #include<vector> #include<string> #include<cstdio> #include<cmath> #include<stack> #include<queue> #include<stack> #include<map> #include<set> #define FF(i, a, b) for(int i=a; i<b; i++) #define FD(i, a, b) for(int i=a; i>=b; i--) #define REP(i, n) for(int i=0; i<n; i++) #define CLR(a, b) memset(a, b, sizeof(a)) #define debug puts("**debug**") #define LL long long #define PB push_back #define eps 1e-10 using namespace std; //hdu 2440 const int maxn = 111; int n, T; struct Point { double x, y; Point (double x=0, double y=0):x(x), y(y) {} }p[maxn], pt[maxn], ft; typedef Point Vector; Vector operator + (Vector A, Vector B) { return Vector(A.x + B.x, A.y + B.y); } Vector operator - (Vector A, Vector B) { return Vector(A.x - B.x, A.y - B.y); } Vector operator * (Vector A, double p) { return Vector(A.x*p, A.y*p); } Vector operator / (Vector A, double p) { return Vector(A.x/p, A.y/p); } bool operator < (const Point& a, const Point& b) { return a.x < b.x || (a.x == b.x && a.y < b.y); } int dcmp(double x) { if(fabs(x) < eps) return 0; return x < 0 ? -1 : 1; } bool operator == (const Point& a, const Point& b) { return dcmp(a.x-b.x) == 0 && dcmp(a.y-b.y) == 0; } double Dot(Vector A, Vector B) { return A.x*B.x + A.y*B.y; } double Length(Vector A) { return sqrt(Dot(A, A)); } double Angel(Vector A, Vector B) { return acos(Dot(A, B) / Length(A) / Length(B)); } double Cross(Vector A, Vector B) { return A.x*B.y - A.y*B.x; } int ConvexHull(Point *p, int n, Point* ch)//凸包 { sort(p, p+n); int m = 0; REP(i, n) { while(m > 1 && Cross(ch[m-1]-ch[m-2], p[i]-ch[m-2]) <= 0) m--; ch[m++] = p[i]; } int k = m; FD(i, n-2, 0) { while(m > k && Cross(ch[m-1]-ch[m-2], p[i]-ch[m-2]) <= 0) m--; ch[m++] = p[i]; } if(n > 1) m--; return m; } inline double dist(Point a, Point b) { return sqrt((a.x - b.x)*(a.x - b.x) + (a.y - b.y)*(a.y - b.y)); } double fermat_point(Point *pt, int n, Point& ptres) { Point u, v; double step = 0.0, curlen, explen, minlen; int i, j, k, idx; bool flag; u.x = u.y = v.x = v.y = 0.0; REP(i, n) { step += fabs(pt[i].x) + fabs(pt[i].y); u.x += pt[i].x; u.y += pt[i].y; } u.x /= n; u.y /= n; flag = 0; while(step > eps) { for(k = 0; k < 10; step /= 2, ++k) for(i = -1; i <= 1; ++i) for(j = -1; j <= 1; ++j) { v.x = u.x + step*i; v.y = u.y + step*j; curlen = explen = 0.0; REP(idx, n) { curlen += dist(u, pt[idx]); explen += dist(v, pt[idx]); } if(curlen > explen) { u = v; minlen = explen; flag = 1; } } } ptres = u; return flag ? minlen : curlen; } int main() { scanf("%d", &T); while(T--) { scanf("%d", &n); REP(i, n) scanf("%lf%lf", &p[i].x, &p[i].y); int m = ConvexHull(p, n, pt); double ans = fermat_point(pt, m, ft); printf("%.0f\n", ans); if(T > 0) puts(""); } return 0; }
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