C语言综合作业：遍一个通讯录管理程序。通讯录应包含以下内容：序号，姓名，电话，地址等内容。具体要求如

1.显示所有已录入的通讯录。
2.实现新纪录的录入。
3.实现删除任何一条记录。
4.实现修改任意一条纪录。
5.可以根据姓名，电话或地址查询等相关信息。
6.系统的推出。

追问：没有吧删除记录的时候出了点问题，再改下。解决了马上采纳其他的要求都满足，不过在删除记录的时候，就终止运行了我电脑里没装C++。今下午上机课后给你回复删除记录的时候出问题了，一删除就程序终止。PS：我要是能改就不会到百度上来找人帮忙了应该变为2哦根据序号就行了啥数据结构哦，这是我们老师布置的C语言综合作业，你看我的昵称嘛我们连数据结构学都没学，话说C语言也挺悲剧的，下一届我们学院这课程就取消了550558136@qq.com   通讯录中没有序号，可不可以改下呢

答案：对数据的存储结构有要求吗？ 

#include <stdio.h>
#include <string.h>

const int MAX_NAME = 99;
const int MAX_PHONE = 27;
const int MAX_ADDR = 127;

typedef struct _PersonInfo 
{
	char name[MAX_NAME + 1];
	char phone[MAX_PHONE + 1];
	char addr[MAX_ADDR + 1];
}PersonInfo ;

const char *ID = "编号：";
const char *NAME = "姓名：";
const char *PHONE = "电话：";
const char *ADDR = "地址：";

const int MAX_NUM = 512;
PersonInfo g_piArry[MAX_NUM];

static int read_line ( FILE *fp, char *line, int max_length )
{
	int i;
	char ch;
	
	/* initialize index to string character */
	i = 0;
	
	/* read to end of line, filling in characters in string up to its
	maximum length, and ignoring the rest, if any */
	for(;;)
	{
		/* read next character */
		ch = fgetc(fp);
		
		/* check for end of file error */
		if ( ch == EOF )
			return -1;
		
		/* check for end of line */
		if ( ch == '\n' )
		{
			/* terminate string and return */
			line[i] = '\0';
			return 0;
		}
		
		/* fill character in string if it is not already full*/
		if ( i < max_length )
			line[i++] = ch;
	}
	
	/* the program should never reach here */
	return -1;
}

void menu_add();
void menu_print();			
void menu_delete();
void menu_modify();
void menu_detail();


/* codes for menu */
#define PRINT_CODE   1
#define ADD_CODE     2
#define DEL_CODE     3
#define MOD_CODE     4
#define DETAIL_CODE  5
#define EXIT_CODE    6

int main(void)
{
	memset(g_piArry, 0, sizeof(g_piArry));

	for(;;)
	{
		int choice, result;
		char line[301];
		
		// FILE *fp1=fopen("input2","r");
		
		
		/* print menu to standard error */
		fprintf ( stderr, "\nOptions:\n" );
		fprintf ( stderr, "%d: 显示所有已录入的通讯录\n",      PRINT_CODE );
		fprintf ( stderr, "%d: 录入新纪录\n",       ADD_CODE );
		fprintf ( stderr, "%d: 删除一条记录\n",  DEL_CODE );
		fprintf ( stderr, "%d: 修改一条纪录\n",    MOD_CODE );
		fprintf ( stderr, "%d: 根据姓名，电话或地址查询相关信息\n",                   DETAIL_CODE );
		fprintf ( stderr, "%d: 退出系统\n",        EXIT_CODE );
		fprintf ( stderr, "\nEnter option: " );
		
		if ( read_line ( stdin, line, 300 ) != 0 ) continue;
		// read_line (fp1 , line, 300 ) ;
		
		//printf("\n-----------%s-----------\n",line);
		
		result = sscanf ( line, "%d", &choice );
		
		if ( result != 1 )
		{
			fprintf ( stderr, "corrupted menu choice\n" );
			continue;
		}
		
		switch ( choice )
		{
		case ADD_CODE: /* add book to database */
			menu_add();
			break;
			
		case PRINT_CODE: /* get book details from database */
			menu_print();
			break;
			
		case DEL_CODE: /* delete book from database */
			menu_delete();
			break;
			
			case MOD_CODE: /* print database contents to screen
				(standard output) */
				menu_modify();
				break;
				
			case DETAIL_CODE: /* print tree to screen (standard output) */
				menu_detail();
				break;
				
				/* exit */
			case EXIT_CODE:
				break;
				
			default:
				fprintf ( stderr, "illegal choice %d\n", choice );
				break;
		}
		
		/* check for exit menu choice */
		if ( choice == EXIT_CODE )
			break;
	}
	
	return 0;  
}

bool isdigit(char n)
{
	if (n <= '9' && n >= '0')
	{
		return true;
	}
	else
	{
		return false;
	}
}

int IsString(char *szBuff)
{
    const int nLen = strlen(szBuff);
    
    int nDigitCnt = 0;
    int nPos = 0;
    for (nPos = 0; nPos < nLen; nPos++)
    {
        if (isdigit(szBuff[nPos]))
        {
            nDigitCnt++;
        }
    }
    
    if (nLen == nDigitCnt)
    {
        fprintf(stderr, "The words(%s) which you entered is digits, enter again!\n", szBuff);
        return 0;
    }
    
    return 1;
}

/* trim the space of the words */
static int trim_space(char *p)
{
    char *q = NULL;
    if(*p != '\0')
    {
        q = p + strlen(p) - 1;
    }
    else
    {
        return -1;
    }
    
    for(; *q == ' '; q--);
    *(q + 1) ='\0';
    
    for(q = p; *q == ' '; q++);
    strcpy(p,q);
    
    return 0;
}

void print_node(PersonInfo *node, int n)
{
	fprintf(stderr, "%s", ID);
	printf("%d\n", n);

	fprintf(stderr, "%s", NAME);
	printf("%s\n", node->name);

	fprintf(stderr, "%s", PHONE);
	printf("%s\n", node->phone);

	fprintf(stderr, "%s", ADDR);
	printf("%s\n", node->addr);
}

void menu_add()
{
	char name[MAX_NAME + 1] = {0};
	char phone[MAX_PHONE + 1] = {0};
	char addr[MAX_ADDR + 1] = {0};

	int nId = 0;
	do
	{
		fprintf(stderr, "%s", ID);
		scanf("%d", &nId);
		getchar();
	}while(nId >= MAX_NUM && nId < 1);
	
    int nLen = 0;
    do
    {
        fprintf(stderr, "%s", NAME);
        fgets(name, MAX_NAME, stdin);
        nLen = strlen(name) - 1;
        name[nLen] = '\0';
        trim_space(name);
    }while (!IsString(name));

    fprintf(stderr, "%s", PHONE);
    fgets(phone, MAX_PHONE, stdin);
    nLen = strlen(phone) - 1;
    phone[nLen] = '\0';

	fprintf(stderr, "%s", ADDR);
    fgets(addr, MAX_ADDR, stdin);
    nLen = strlen(addr) - 1;
    addr[nLen] = '\0';

	nId = nId - 1;
	PersonInfo *pi = &g_piArry[nId];
	if (0 != strlen(pi->name))
	{
		int i = 0;
		for (i = MAX_NUM; i > nId; i--)
		{
			memcpy(&g_piArry[i], &g_piArry[i - 1], sizeof(PersonInfo));
		}
	}

	strcpy(pi->name, name);
	strcpy(pi->phone, phone);
	strcpy(pi->addr, addr);
	

	return;
}

void menu_print()
{
	int n = 0;
	for (n = 0; n < MAX_NUM; n++)
	{
		if (0 != strlen(g_piArry[n].name))
		{
			print_node(&g_piArry[n], n + 1);
		}		
	}
	return;
}
		
void menu_delete()
{
	int nId = 0;
	do
	{
		fprintf(stderr, "%s", ID);
		scanf("%d", &nId);
		getchar();
	}while(nId >= MAX_NUM && nId < 1);

	PersonInfo *pi = &g_piArry[nId];

	int i = 0;
	for (i = nId - 1; i < MAX_NUM - 1; i++)
	{
		memcpy(&g_piArry[i], &g_piArry[i + 1], sizeof(PersonInfo));
	}

	fprintf(stderr, "删除成功(%s)", nId);
	return ;
}

void menu_modify()
{
	int nId = 0;
	do
	{
		fprintf(stderr, "%s", ID);
		scanf("%d", &nId);
		getchar();
	}while(nId >= MAX_NUM && nId < 1);
	
	char name[MAX_NAME + 1] = {0};
	char phone[MAX_PHONE + 1] = {0};
	char addr[MAX_ADDR + 1] = {0};
	int nLen = 0;

	do
    {
        fprintf(stderr, "%s", NAME);
        fgets(name, MAX_NAME, stdin);
        nLen = strlen(name) - 1;
        name[nLen] = '\0';
        trim_space(name);
    }while (!IsString(name));

	fprintf(stderr, "%s", PHONE);
    fgets(phone, MAX_PHONE, stdin);
    nLen = strlen(phone) - 1;
    phone[nLen] = '\0';
	
	fprintf(stderr, "%s", ADDR);
    fgets(addr, MAX_ADDR, stdin);
    nLen = strlen(addr) - 1;
    addr[nLen] = '\0';
	
	nId = nId - 1;

	PersonInfo *pi = &g_piArry[nId];
	strcpy(pi->name, name);
	strcpy(pi->phone, phone);
	strcpy(pi->addr, addr);

	return ;
}
void menu_detail()
{
	int nId = 0;
	do
	{
		fprintf(stderr, "%s", ID);
		scanf("%d", &nId);
		getchar();
	}while(nId >= MAX_NUM && nId < 1);

	print_node(&g_piArry[nId - 1], nId);

	return;
}

其他：比如之前有3条记录，他们的序号为1、2、3，删除第二条记录之后，第三条记录的序号是仍然为3还是变为2？ 需求再明确一下：
1.比如之前有3条记录，他们的序号为1、2、3，删除第二条记录之后，第三条记录的序号是仍然为3还是变为2？ 
2.删除和修改记录的时候分别根据什么进行删除或修改？序号？名字？还是其它？ 假设记录通讯录的表名为：TList
1. select * from TList
2. insert into TList(...) values(...)
3.delete from TList where ...
4.update TList set ... Where...
5.select * from TList Where name=? or name='' ....
界面用C++写，数据库就用SQL SERVER，简单方面。 同志是哪的？怎么中国的数据结构都一个题目？ 你QQ或是邮箱多少，我把源文件发给你。

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