C语言指针并不难
C语言的核心在于指针，这2个指针题目，如果你不用编译就能得出正确的答案，那你一定是C的高手，不择不扣的高手—指针并不难！第一题：求p[-1]、p[-5]的值#include <stdio.h>int main(void){char* p = NULL;char* tmp = "12345678";p = (char* )(tmp+4);//p[-1] = ?, p[-5] = ?。return 0;}第二题：求p[0]--p[5]的值#include <stdio.h>int main(void){char* data = "12345678";short* tmp = NULL;char p[6] = {0};tmp = (short *)&p[2];*tmp = atoi(&data[4]);//p[0] = ?, p[1] = ?, p[2] = ?, p[3] = ?, p[4] = ?, p[5] = ?。return 0；}如果你觉得意犹未尽，那就再来一个吧：int* p = (int* )0x1234;printf("p = %p, *p = %d\n", p, *p);这个题的答案你总该知道吧。。。。。。
补充：软件开发 , C语言 ,
